First slide

Projection Under uniform Acceleration

Question

The velocity of a projectile at the initial point A is $(2 \hat{i} + 3 \hat{j}) m / s$ . It's velocity (in m/s) at point B is

Easy

A

$2 \hat{i} - 3 \hat{j}$
B

$2 \hat{i} + 3 \hat{j}$
C

$- 2 \hat{i} - 3 \hat{j}$
D

$- 2 \hat{i} + 3 \hat{j}$

Solution

At point B X component of velocity remains unchanged while Y component reverses its direction.
$∴$ The velocity of the projectile at point B is $2 \hat{i} - 3 \hat{j} m / s$

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