The velocity of sound varies according to the relation :c(x)=c0(1+0.1x/d) between a source located at x = 0 and a cliff located at x = d. The time taken for sound to travel from A to B and return back to A is given by
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a
2dc0
b
2dc01+0.12
c
2dc0×1.1
d
20dc0ln(1.1)
answer is D.
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Detailed Solution
Time to reach B from A=tAB=∫x=0d dxc(x)=d0.1c0ln(1.1); total time =2tAB