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Velocity of sound waves in air is 330 m/sec. For a particular sound in air, a path difference of 40 cm is equivalent to a phase difference of 1.6 $π$ . The frequency of this wave is

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165 Hz

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330 Hz

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detailed solution

Correct option is C

Phase difference = 2πλ×path difference⇒1.6π=2πλ×40⇒λ=50cm=0.5m⇒v=nλ⇒330=0.5×n⇒n=660 Hz

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Velocity of sound waves in air is 330 m/sec. For a particular sound in air, a path difference of 40 cm is equivalent to a phase difference of 1.6 π. The frequency of this wave is

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Velocity of sound waves in air is 330 m/sec. For a particular sound in air, a path difference of 40 cm is equivalent to a phase difference of 1.6 $π$ . The frequency of this wave is