First slide

Introduction to waves

Question

Velocity of sound waves in air is 330 m/sec. For a particular sound in air, a path difference of 40 cm is equivalent to a phase difference of 1.6 $π$ . The frequency of this wave is

Easy

A

165 Hz
B

150 Hz
C

660 Hz
D

330 Hz

Solution

Phase difference = $\frac{2 π}{λ} \times$ path difference
$\Rightarrow 1 .6 π = \frac{2 π}{λ} \times 40 \Rightarrow λ = 50 cm = 0 .5 m$
$\Rightarrow v = nλ \Rightarrow 330 = 0 .5 \times n \Rightarrow n = 660 Hz$

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