Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Velocity versus displacement graph of a particle moving in a straight line as shown in figure. The acceleration of the particle

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

is constant

b

increases linearly with x

c

increases parabolically with x

d

None of these

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

From the graph, velocity-displacement equation can be written as v=v0+αx …….(i)Here v0 and α are positive constants. Differentiating Eq. (i) with respect to x, we get dvdx=α= constant Acceleration of the particle can be written as a=vdvdx=v0+αxαThe a-x equation is a linear equation. Thus acceleration increases linearly with x.
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring