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Questions  

The velocity of waves in a string fixed at both ends is 2 m/s. The string forms standing waves with nodes 5.0 cm apart. The frequency of vibration of the string in Hz is

a
40
b
30
c
20
d
10

detailed solution

Correct option is C

Here λ2=5.0 cm     ⇒λ=10cmHence n=vλ=20010=20Hz

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A wire having a linear density of 5 g/m is stretched between two rigid supports with a tension of 450 N. It is observed that the wire resonates at a frequency of 420 Hz. The next highest frequency at which the same wire resonates is 490 Hz. Find the length of the wire. (in m)


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