First slide

Stationary waves

Question

The velocity of waves in a string fixed at both ends is 2 m/s. The string forms standing waves with nodes 5.0 cm apart. The frequency of vibration of the string in Hz is

Easy

A

40
B

30
C

20
D

10

Solution

Here $\frac{λ}{2} = 5 .0 cm \Rightarrow λ = 10 cm$
Hence $n = \frac{v}{λ} = \frac{200}{10} = 20 Hz$

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