Q.
The velocity-time graph of a particle moving in a straight line is shown in figure. The mass of the particle is 2 kg. Work done by all the forces acting on the particle in time interval between t = 0 to t = 10 s is
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a
300 J
b
-300 J
c
400 J
d
-400 J
answer is A.
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Detailed Solution
From work-energy theorem, W=ΔKE=Kf−Ki=12mvf2−vi2=12×2(−20)2−(10)2=300J
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