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Q.

The velocity-time graph of a particle moving in a straight line is shown in figure. The mass of the particle is 2 kg. Work done by all the forces acting on the particle in time interval between t = 0 to t = 10 s is

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a

300 J

b

-300 J

c

400 J

d

-400 J

answer is A.

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Detailed Solution

From work-energy theorem, W=ΔKE=Kf−Ki=12mvf2−vi2=12×2(−20)2−(10)2=300J

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