Velocity-time graph of a particle performing SHM is as shown in Fig.Amplitude of oscillation is then nearly:

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20 cm

48 cm

75 cm

8 cm

answer is B.

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Detailed Solution

In given diagram vmax=3 ms-1and T2=0.75-0.25 ⇒ T=1 sec A=vmax2πT=32×3.141=48 cm

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