First slide

Simple hormonic motion

Question

Velocity-time graph of a particle performing SHM is as shown in Fig.Amplitude of oscillation is then nearly:

Moderate

A

20 cm
B

48 cm
C

75 cm
D

8 cm

Solution

In given diagram $v_{\max} = 3 {ms}^{- 1} and \frac{T}{2} = 0.75 - 0.25 \Rightarrow T = 1 \sec A = \frac{v_{\max}}{\frac{2 π}{T}} = \frac{3}{\frac{2 \times 3.14}{1}} = 48 cm$

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