First slide

Measurement

Question

A vernier calipers having 1 main scale division = $0.1 cm$ is designed to have a least count of $0.02 cm$ . If n be the number of divisions on vernier scale and m be the length of vernier scale, then

Moderate

A

$n = 10, m = 0.5 cm$
B

$n = 9, m = 0.4 cm$
C

$n = 10, m = 0.8 cm$
D

$n = 10, m = 0.2 cm$

Solution

$1 MSD = 0.1 cm$
$L C = 1 M S D - 1 V S D$
$0.02 cm = 0.1 cm - 1 VSD$
$1 VSD = 0.1 - 0.02 = 0.08 cm$
$1 V S D = \frac{l e n g t h o f v e r e n i e r s c a l e}{n o . o f d i v i s i o n s} = 0.08 cm \frac{m}{n} = 0.08 c m$
only option (3) satisfy it.

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App