A vernier calliper is having 1 main scale division = 1 mm. Ten divisions of vernier scale coincide. with nine divisions of main scale. If two jaws of instrument touch each other, the 8 th division of vernier scale coincide with a mark of main scale and the zero of the vernier scale lies to the right of the zero of main scale. While measuring the length of cylinder, the zero of the vernier seale lies slightly to the left of 3.2 cm and the fourth vernier division coincides with a mark of the length cylinder is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
3.06 cm
b
3.15 cm
c
3.16 cm
d
3.22 cm
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Least count = 1 mm-0.9 mm=0.1 mmReading = Main scale reading + Vemier scale reading - |zero error|=3.1 cm+4×0.1 mm-0.8 mm=(3.1+0.04-0.08)cm= 3.06 cm
A vernier calliper is having 1 main scale division = 1 mm. Ten divisions of vernier scale coincide. with nine divisions of main scale. If two jaws of instrument touch each other, the 8 th division of vernier scale coincide with a mark of main scale and the zero of the vernier scale lies to the right of the zero of main scale. While measuring the length of cylinder, the zero of the vernier seale lies slightly to the left of 3.2 cm and the fourth vernier division coincides with a mark of the length cylinder is