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The vernier constant of a travelling microscope is 0.001 cm. If 49 main scale divisions coincide with 50 vernier scale divisions, then the value of 1 main scale division is

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0.1 mm

0.5 mm

0.4 mm

1 mm

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detailed solution

Correct option is B

50VSD=49MSD1VSD=4950MSD⇒VC=1MSD−1VSD⇒VC=1MSD−4950MSD ⇒VC=150MSD⇒1MSD=50(VC)=50(0.001cm)⇒1MSD=0.05cm=0.5mm⇒1MSD=0.5mm

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I am a vernier calipers. I have a task to measure the length of a pencil as shown in the figure. The vernier constant of my vernier scale is 0.05 times the value of one division of main-scale.

My Vernier Scale has n-divisions and coincides with (n – 4) divisions of main scale. While measuring the length of pencil, the $\frac{n}{5}$ th division of Vernier-Scale exactly coincides with a division of main-scale. Neglect any zero error.
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