First slide

Measurement

Question

The vernier constant of a vernier callipers is $0.001 cm$ . If $49$ main scale divisions coincide with $50$ vernier scale divisions, then the value of $1$ main scale division is

Moderate

A

0.1 mm
B

0.5 mm
C

0.4 mm
D

1 mm

Solution

$50 VSD = 49 MSD$
$1 VSD = \frac{49}{50} MSD$
$V C = 1 MSD - 1 VSD$
$V C = 1 MSD - \frac{49}{50} MSD$
$V C = \frac{1}{50} M S D$
$1 MSD = 50 (VC)$
$= 50 (0.001 cm)$
$1 MSD = 0.5 mm$

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