First slide

Applications of SHM

Question

The vertical extension in a light spring by a weight of 1 kg suspended from the wire is 9.8 cm. The period of oscillation

Moderate

A

$20 πsec$
B

$2 πsec$
C

$2 π / 10 \sec$
D

$200 πsec$

Solution

$∵ mg = kx \Rightarrow \frac{m}{k} = \frac{x}{g} \Rightarrow T = 2 π \sqrt{\frac{m}{k}} = 2 π \sqrt{\frac{x}{g}}$
$= 2 π \sqrt{\frac{9 .8 \times 10^{- 2}}{9 .8}} = \frac{2 π}{10} \sec$

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