First slide

Vertical projection from ground

Question

The vertical height of point P above the ground is twice that of Q. A particle is projected downward with a speed of $5 {ms}^{- 1}$ from P and at the same time, another particle is projected upward with the same speed from Q. Both particles reach the ground simultaneously, then

Moderate

A

PQ = 30 m
B

time of flight of stones = 3 s
C

Both (a) and (b) are correct
D

Both (a) and (b) are wrong

Solution

$h = - 5 t + 5 t^{2} and 2 h = 5 t + 5 t^{2}$
From these two equations, we get t = 3 s and h = distance between P and Q = 30 m .

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