A vertical spring with force constant 'k' is fixed on a table. A ball of mass 'm' at a height 'h' above the free upper end of the spring falls vertically on the spring so that the spring is compressed by a distance 'd'. The net work done in the process is
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a
b
mgh+d=12kd2
c
mgh-d-12kd2
d
mgh-d+12kd2
answer is B.
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Detailed Solution
Total displacement = (h+d)Work done by gravity = mg(h+d)Work done by the spring on the ball =12kd2Therefore Total work done =mgh+d=12kd2