First slide
Fluid dynamics
Question

In a vertical tube of variable cross section water is flowing as shown in figure. If p1 and p2 be respectively, then

Moderate
Solution

By Bernoulli's equation

p1 +12ρv12=p2+12ρv22+ρghp1p2=12ρv22v12+ρgh

By continuity equation, V1>V2. So the quantity 12ρv22v12 is always negative. So for some value of ‘h , p1p2 is zero.

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