First slide

The bar magnet

Question

A very long magnet of pole strength 16 A-m is placed vertically with its one pole on the table. At what distance from the pole, there will be a neutral point on the table. (B_H = 4 × 10^–5 Wbm^–2)

Moderate

A

0.4 m
B

0.2 m
C

0.6 m
D

0.8 m

Solution

$\begin{array}{rcl} B_{H} & = & \frac{μ_{0}}{4 π} \frac{m}{d^{2}}; \\ 4 x 10^{- 5} & = & 10^{- 7} \frac{16}{d^{2}} \end{array}$
d² = 0.04,
d = 0.2 m

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App