A very long magnet of pole strength 16 A-m is placed vertically with its one pole on the table. At what distance from the pole, there will be a neutral point on the table. (BH = 4 × 10–5 Wbm–2)

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0.4 m

0.2 m

0.6 m

0.8 m

answer is B.

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Detailed Solution

BH=μ04πmd2 ; 4 x 10-5=10-716d2d2 = 0.04, d = 0.2 m

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