A very long straight conducting wire, lying along the z-axis, carries a current of 2 A. The integral ∮B→·dl→ computed along the straight line PQ, where P has the coordinates (2 cm, 0, 0) and Q has the coordinates (2 cm, 2 cm, 0). The integral has the magnitude (in SI units)
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a
π2×10-7
b
8π×10-7
c
2π×10-7
d
π×10-7
answer is D.
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Detailed Solution
∫PAQB→·dl→=∫RBQB→·dl→ ∵∫PCRB→·dl→=0 =μ0I2πRπ4R =4π×10-7(2)8=π×10-7 S.I. units