First slide

Surface tension

Question

A very narrow capillary tube records a rise of 20 cm when dipped in water. When the area of cross-section is reduced to one-fourth of the former value, water will rise to a height of:

Easy

A

10 cm
B

20 cm
C

40 cm
D

80 cm

Solution

$h \infty \frac{1}{r} \Rightarrow h_{2} = (\frac{r_{1}}{r_{2}}) h_{1} \Rightarrow h_{2} = (\frac{r}{r / 2}) \times 20 cm = 40 cm .$

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