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A vessel of area of cross-section $A$ has liquid to a height $H$ . There is a hole at the bottom of vessel having area of cross-section $a$ . The time taken to decrease the level from $H_{1}$ to $H_{2}$ will be:

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Aa2g(H1−H2)

2gh

2gh(H1−H2)

Aag2(H1−H2)

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detailed solution

Correct option is A

The average velocity of efflux v=2gH1+2gH22 Let t be the time taken to empty the tank from level H1 to H2 . Then,2gH1+2gH22×a×t=A[H1−H2] g2[H1+H2]at =A[H1+H2][H1−H2] or t=Aa2g×(H1−H2)

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A vessel of area of cross-section A has liquid to a height H . There is a hole at the bottom of vessel having area of cross-sectiona . The time taken to decrease the level from H1 to H2 will be:

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A vessel of area of cross-section $A$ has liquid to a height $H$ . There is a hole at the bottom of vessel having area of cross-section $a$ . The time taken to decrease the level from $H_{1}$ to $H_{2}$ will be: