A vessel of area of cross-section A has liquid to a height H . There is a hole at the bottom of vessel having area of cross-sectiona . The time taken to decrease the level from H1 to H2 will be:
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a
Aa2g(H1−H2)
b
2gh
c
2gh(H1−H2)
d
Aag2(H1−H2)
answer is A.
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Detailed Solution
The average velocity of efflux v=2gH1+2gH22 Let t be the time taken to empty the tank from level H1 to H2 . Then,2gH1+2gH22×a×t=A[H1−H2] g2[H1+H2]at =A[H1+H2][H1−H2] or t=Aa2g×(H1−H2)