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Q.

A vessel contains an immiscible mixture of water and a liquid of density 0.8 gm/cc. A cube of side 10 cm is placed in the mixture and it is observed that the water-liquid interface is at the middle of cube height.Mass of the cube is:

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a

420 gm

b

680 gm

c

225 gm

d

900 gm

answer is D.

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Detailed Solution

Volume of cube =(10)3=1000 cm3In floating condition W=Vρg=(Vin)1ρoilg+(Vin)2 ρwter g m=500×0.8+500×1=900 gm
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