First slide

Fluid statics

Question

A vessel contains an immiscible mixture of water and a liquid of density 0.8 gm/cc. A cube of side 10 cm is placed in the mixture and it is observed that the water-liquid interface is at the middle of cube height.Mass of the cube is:

Moderate

A

420 gm
B

680 gm
C

225 gm
D

900 gm

Solution

Volume of cube $= {(10)}^{3} = 1000 {cm}^{3}$
In floating condition
$W = V ρ g = {(V_{in})}_{1} ρ_{oil} g + {(V_{in})}_{2} ρ_{wter} g m = 500 \times 0.8 + 500 \times 1 = 900 gm$

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