A vessel of depth 2h is half filled with a liquid of refractive index 22 and the upper half with another liquid of refractive index 2. The liquids are immiscible. The apparent depth of the inner surface of the bottom of vessel will be :

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h32

h22+1

34h2

answer is D.

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Detailed Solution

Apparent depth=h1μ1+h1μ2=h122+h12=32h4

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