First slide

Fluid statics

Question

A vessel with water is placed on a weighing pan and reads 600 g. Now a ball of 40 g and density 0.80 g/cc is sunk into the water with a pin as shown in fig. keeping it sunk. The weighing pan will show a reading

Difficult

A

600 g
B

550 g
C

650 g
D

632 g

Solution

Upthrust on ball = weight of displaced water
$= V σg = (\frac{m}{ρ}) σ g = \frac{40}{0.8} \times 1 \times g = 50 g$
As the ball is sunk into the water with a pin by applying downward force equal to upthrust on it.
So reading of weighing pan
= weight of water + downward force against upthrust
= 600 + 50 = 650 gm

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