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Q.

Visible light of wavelength  6000×10−8cm falls normally on a single slit and produces a diffraction pattern. It is found that the second diffraction minimum is at  600 from the central maximum. If the first minimum is produced at  θ1, then  θ1, is close to,

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a

250

b

450

c

200

d

300

answer is A.

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Detailed Solution

For 2nd minima  dsinθ=2λ  Since ,θ=600 ,  sinθ=32given               ⇒λd=34______i So for 1st minima is     dsinθ1=λ ⇒sinθ1=λd=34 from equation (1)    ⇒θ=25.65º⇒θ≈25º
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