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1\vo charges of 4μC each are placed at the comers A and B of an equilateral triangle of side length 0.2 m in air. The electric potential at C is $[\frac{1}{4 {πε}_{0}} = 9 \times 10^{9} \frac{N - m^{2}}{C^{2}}]$

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9 X 104 V

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detailed solution

Correct option is C

Potential at C=9×109×4×10-60.2×2=36×104 V

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1\vo charges of 4μC each are placed at the comers A and B of an equilateral triangle of side length 0.2 m in air. The electric potential at C is14πε0=9×109N-m2C2

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1\vo charges of 4μC each are placed at the comers A and B of an equilateral triangle of side length 0.2 m in air. The electric potential at C is $[\frac{1}{4 {πε}_{0}} = 9 \times 10^{9} \frac{N - m^{2}}{C^{2}}]$