Questions
A 50 volt battery is connected across 10 ohm resistor. The current is 4. 5 ampere. The internal resistance of the battery is
a
zero
b
0 .5 ohm
c
1.1ohm
d
5.0 ohm
detailed solution
Correct option is C
Let r be the internal resistance of the cell. Theni=E(R+r)4⋅5=50(10+r)Solving, we get r=1⋅1ΩTalk to our academic expert!
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An energy source will supply a constant current into the load if its internal resistance is
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