First slide

Cell

Question

A 50 volt battery is connected across 10 ohm resistor. The current is 4. 5 ampere. The internal resistance of the battery is

Moderate

A

zero
B

0 .5 ohm
C

1.1ohm
D

5.0 ohm

Solution

Let r be the internal resistance of the cell. Then
$\begin{array}{l} i = \frac{E}{(R + r)} \\ 4 \cdot 5 = \frac{50}{(10 + r)} \end{array}$
Solving, we get $r = 1 \cdot 1 Ω$

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