The voltage of an ac source varies with time according to the equation V=100sin⁡100πcos⁡100πt where t is in seconds and V is in volts. Then

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

The peak voltage of the source is 100 volts

The peak voltage of the source is 50 volts

The peak voltage of the source is 100/2volts

The frequency of the source is 50 Hz

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

V=50×2sin⁡100πtcos⁡100πt=50sin⁡200πt⇒V0=50 Volts and v=100Hz

Watch 3-min video & get full concept clarity