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The voltage of an ac source varies with time according to the equation $V = 100 \sin 100 πcos 100 πt$ where t is in seconds and V is in volts. Then

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The peak voltage of the source is 100 volts

The peak voltage of the source is 50 volts

The peak voltage of the source is 100/2volts

The frequency of the source is 50 Hz

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detailed solution

Correct option is B

V=50×2sin⁡100πtcos⁡100πt=50sin⁡200πt⇒V0=50 Volts and v=100Hz

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The voltage of an ac source varies with time according to the equation V=100sin⁡100πcos⁡100πt where t is in seconds and V is in volts. Then

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

The voltage of an ac source varies with time according to the equation $V = 100 \sin 100 πcos 100 πt$ where t is in seconds and V is in volts. Then