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Questions  

A voltmeter having a resistance of 998    Ω is connected to a cell of emf 2 V and internal resistance 2  Ω. The error in the measurement of emf will be

a
4 ×  10−1V
b
2 ×  10−3V
c
4 ×  10−3V
d
2 ×  10−1V

detailed solution

Correct option is C

Error in measurement - Actual value Measured valueActual value = 2V i=2998+2=1500 ASince  E=V+ir ⇒  V=E −ir  =2  −1500 × 2=998500 V∴  Measured value  =998500 V⇒  Error=2−998500 =4 ×  10−3V

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Similar Questions

Resistances R1 and R2, each of 60  Ω, are connected in series as shown in figure. The potential difference between A and B is kept 120 volt. what will be the reading of voltmeter connected between the points C and D if resistance of voltmeter is 120  Ω?


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