A voltmeter with resistance 500 Ω is used to measure the emf of a cell of internal resistance 4 Ω. The percentage error in the reading of the voltmeter will be

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0.2%

0.8%

1.4%

0.4%

answer is B.

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Detailed Solution

I=E500+4=E504Reading of voltmeter =500 I =500 E504%error = E− 500 E504E × 100 = 400504 = 0.8%

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