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A voltmeter with resistance 500  Ω is used to measure the emf of a cell of internal resistance 4Ω. The percentage error in the reading of the voltmeter will be

a
0.2%
b
0.8%
c
1.4%
d
0.4%

detailed solution

Correct option is B

I=E500+4=E504Reading of voltmeter  =500 I =500 E504%error = E− 500 E504E  ×  100 = 400504 = 0.8%

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