First slide

voltmeter

Question

A voltmeter with resistance $500 Ω$ is used to measure the emf of a cell of internal resistance $4 Ω$ . The percentage error in the reading of the voltmeter will be

Moderate

A

0.2%
B

0.8%
C

1.4%
D

0.4%

Solution

$I = \frac{E}{500 + 4} = \frac{E}{504}$
Reading of voltmeter $= 500 I = \frac{500 E}{504}$
$% error = \frac{E - \frac{500 E}{504}}{E} \times 100 = \frac{400}{504} = 0 .8 %$

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