Questions
A voltmeter with a resistance of 50 x103 ohm is used to measure voltage in a circuit. To increase its range to 3 times, the additional resistance to be put in series is
detailed solution
Correct option is A
R=V′ig−G=nVV/R0−R0where Ro is the resistance of voltmeter∴ R=nR0−R0=(n−1)R0=(3−1)×50×103=100×103=105ΩTalk to our academic expert!
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