First slide

Temperature and heat-thermal properties of matter

Question

The volume of an air bubble becomes three times as it rises from the bottom of a lake to its surface. Assuming atmospheric pressure to be 75 cm of Hg and the density of water to be 1/10 of the density of mercury, the depth of the lake is

Moderate

A

5 m
B

10 m
C

15 m
D

20 m

Solution

$\begin{array}{l} P_{1} V_{1} = P_{2} V_{2} \Rightarrow (H_{Hg} ρ_{Hg} + H_{W} ρ_{W}) V = H_{Hg} ρ_{Hg} \times 3 V \\ \Rightarrow H_{Hg} ρ_{Hg} + H_{W} \frac{ρ_{Hg}}{10} = 3 H_{Hg} ρ_{Hg} \\ \Rightarrow H_{W} = 2 H_{Hg} \times 10 = \frac{2 \times 75 \times 10}{100} = 15 m \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App