Q.

The volume of an air bubble becomes three times as it rises from the bottom of a lake to its surface. Assuming atmospheric pressure to be 75 cm of Hg and the density of water to be 1/10 of the density of mercury, the depth of the lake is

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a

5 m

b

10 m

c

15 m

d

20 m

answer is C.

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Detailed Solution

P1V1=P2V2⇒HHgρHg+HWρWV=HHgρHg×3V⇒HHgρHg+HWρHg10=3HHgρHg⇒HW=2HHg×10=2×75×10100=15m
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