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The volume of an air bubble becomes three times as it rises from the bottom of a lake to its surface. Assuming atmospheric pressure to be 75 cm of Hg and the density of water to be 1/10 of the density of mercury, the depth of the lake is

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By Expert Faculty of Sri Chaitanya
a
5 m
b
10 m
c
15 m
d
20 m
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detailed solution

Correct option is C

P1V1=P2V2⇒HHgρHg+HWρWV=HHgρHg×3V⇒HHgρHg+HWρHg10=3HHgρHg⇒HW=2HHg×10=2×75×10100=15m


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