The volume of a gas is reduced adiabatically to (14) of its volume at 270C. If γ = 1.4, the new temperature will be

For adiabatic change the relation between temperature and volume isTVγ-1 = constantwhere γ is ratio of specific heats of the gas,Given, T1 = 27 + 273 = 300  K, V1 = V, V2 = V4T1Vγ-11 = T2Vγ-12⇒ T2 = (V1V2)γ-1×T1             = (VV4)1.4-1×300            = (4)0.4×300 = 300 × (4)0.4K