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# Volume of mercury in the bulb of a thermometer is  ${\text{10}}^{\text{-6}}{\text{m}}^{\text{3}}$, area of cross section of capillary tube is $\text{2}×{\text{10}}^{\text{-7}}{\text{m}}^{2}$ . If the temperature is raised by ${100}^{\circ }\text{C}$ , the length of mercury is (${\text{γ}}_{\mathrm{Hg}}\text{=18}×{{10}^{-5}}^{\text{\hspace{0.17em}}\circ }{\text{C}}^{\text{-1}}$ )

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By Expert Faculty of Sri Chaitanya
a
9 cm
b
9 mm
c
18 cm
d
5 cm
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detailed solution

Correct option is A

volume of mercury in the bulb of thermometer is  V=10-6m3:  area of cross section of capillarty tube is A=2×10-7m2  change in temperature is ΔT=100oClength of mercury in the tube is l=?real expansion of mercury is γreav=γr=18×10-5∘c−1  γr =ΔVV.Δt  γr=A×lV.Δt  l=γr.V.ΔtA  substitute the given valuesl=18×10−5×10−6×1002×10−7  l=9×10-2m  L=9 cm

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