Volume of mercury in the bulb of a thermometer is $$10-6m3$$, area of cross section of capillary tube is $$2$$×$$10-7m2$$ . If the temperature is raised by $$100$$∘C , the length of mercury is $$($$γ$$Hg=18$$×$$10$$−$$5$$ ∘$$C-1$$ $$)$$

Question

Volume of mercury in the bulb of a thermometer is  $$10-6m3$$, area of cross section of capillary tube is $$2$$×$$10-7m2$$ . If the temperature is raised by $$100$$∘C , the length of mercury is $$($$γ$$Hg=18$$×$$10$$−$$5$$ ∘$$C-1$$ $$)$$

Infinity Learn · Accepted Answer

volume of mercury in the bulb of thermometer is  $$V=10-6m3$$:  area of cross section of capillarty tube is $$A=2$$×$$10-7m2$$  change in temperature is Δ$$T=100oClength$$ of mercury in the tube is $$l=$$?real expansion of mercury is γ$$reav=$$γ$$r=18$$×$$10-5$$∘c−$$1$$  γr $$=$$ΔVV.Δt  γ$$r=A$$×lV.Δt  $$l=$$γr.V.ΔtA  substitute the given $$valuesl=18$$×$$10$$−$$5$$×$$10$$−$$6$$×$$1002$$×$$10$$−$$7$$  $$l=9$$×$$10-2m$$  $$L=9$$ cm

Volume of mercury in the bulb of a thermometer is $10^{-6} m^{3}$ , area of cross section of capillary tube is $2 \times 10^{-7} m^{2}$ . If the temperature is raised by $100^{\circ} C$ , the length of mercury is ( $γ_{Hg} =18 \times {10^{- 5}}^{\circ} C^{-1}$ )

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Volume of mercury in the bulb of a thermometer is 10-6m3, area of cross section of capillary tube is 2×10-7m2 . If the temperature is raised by 100∘C , the length of mercury is (γHg=18×10−5 ∘C-1 )

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Volume of mercury in the bulb of a thermometer is $10^{-6} m^{3}$ , area of cross section of capillary tube is $2 \times 10^{-7} m^{2}$ . If the temperature is raised by $100^{\circ} C$ , the length of mercury is ( $γ_{Hg} =18 \times {10^{- 5}}^{\circ} C^{-1}$ )