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Q.

The volume V of an enclosure contains a mixture of three gases, 32 g of oxygen, 28 g of nitrogen and 44 g of carbon dioxide at absolute temperature T. Consider R as universal gas constant. The pressure of the mixture of gases is:

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a

4RTV

b

88RTV

c

3RTV

d

52RTV

answer is C.

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Detailed Solution

Moles of oxygen = 3232=1Moles of nitrogen=2828=1Moles of carbon dioxide=4444=1Total pressure = Sum of partial pressuresP=PO 2+PN 2+PCO2 =RTV+RTV+RTV=3RTV
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