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The volume (V) of a monatomic gas varies with its temperature (T) as shown in the graph. The ratio of work done by the gas, to the heat absorbed by it, when it undergoes a change from state A to state B, is

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a
25
b
23
c
13
d
27

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detailed solution

Correct option is A

Given process is isobaric.∴  dQ=nCpdT; where Cp is specific heat at constant pressure. or   dQ=n52RdT Also, dW=PdV=nRdT Required ratio =dWdQ=nRdTn52RdT=25

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