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A volume V of a viscus liquid flows per unit time due to a pressure head ΔPalong a pipe of diameter d and length d/2 and length 2l is connected to the same pressure head ΔP Now the volume of the liquid flowing per unit time is

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a

V/16

b

V/8

c

V/4

d

V

answer is B.

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Detailed Solution

We know that V=πPr48ηl=π(ΔP)(d/2)48ηl=π(ΔP)d4128ηl In second case, V1=π(ΔP)(d/4)48η×(2l)=132V with four tubes, that volume of liquid flowing =4×V32=V8

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