In the V-T graph shown in the figure. Match the Column I with Column II and mark the correct option from the codes given below.
Column I Column II
(A) Gas A is (p) Monoatomic
(B) p_A/p_B is (q) Diatomic
(C) n_A/n_B is (r) > 1
(D) Gas B is (s) < 1
(t) Cannot say anything
Codes
A B C D

Moderate

Solution

From the given V-T graph, we cannot tell the nature of gas.
$V = \frac{n R T}{p} = (\frac{n R}{p}) T$
If p is constant, V-T graph is a straight line. Slope of this line is $\frac{n R}{p} .$
Here, (Slope)_A > (Slope)_B
$\Rightarrow {(\frac{n R}{p})}_{A} > {(\frac{n R}{p})}_{B}$
So, either $\frac{n_{A}}{n_{B}}$ may be greater than 1 or $\frac{p_{A}}{p_{B}}$ may be less than 1.
But it certain that ${(\frac{n}{p})}_{A} > {(\frac{n}{p})}_{B} .$
Hence, A $\to$ t, B $\to$ t, C $\to$ t, D $\to$ t.

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