10-3 W of 5000 Å light is directed on a photoelectric cell. If the current in the cell is 0.16 μA, the percentage of incident photons which produce photoelectrons, is

Number of photons falling per second:Np=10-36.6×10-34×3×1085000×10-10No of electrons per unit time =IePercentage of photons producing photoelectrons = NeNp×100=10122.5×1015×100=0.04%