Questions
A 100 W bulb B1 and two 60 W bulbs B2 and B3 are connected to a 250 V source, as shown in the figure. Now W1, W2 and W3 are the output powers of the bulbs B1, B2 and B3, respectively. Then
detailed solution
Correct option is D
P=V2R so R=V2P ⇒ R1 = V2100 and R2=R3=V260Now W1 =2502R1+R22. R1, W2 =2502R1+R22. R2and W3 =2502R3W1 : W2 : W3 = 15 : 25 : 64 or W1 < W2 < W3Talk to our academic expert!
Similar Questions
A resistor R is connected across a battery of emf 12 V. It observed that terminal potential differenceis 9 V and the power delivered to resistor is 18 W. Internal resistance of the battery ‘r’ and the resistance R are respectively
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests