An 80W galvanometer deflects full-scale for a potential of 20 mV. A voltmeter deflecting full-scale of 5 V is to be made using this galvanometer. We must connect
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a
a resistance of 20kW parallel to the galvanometer
b
a resistance of 19.92 kW parallel to the galvanometer
c
a resistance of 19.92 kW in series with the galvanometer
d
a resistance of 20kW in series with the galvanometer
answer is C.
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Detailed Solution
The current through the galvanometer producing full-scale deflection is I=VR=20×10−380=2.5×10−4A. To convert the galvanometer into a voltmeter, a high resistance is connected in series with the galvanometer. Therefore, 5 V = (2.5 × 10-4)(R + 80) or R = 19.92 kW.