W1, W2 and W3 are the different vertical widths of windows 1, 2 and 3 respectively placed in a vertical plane. A particle is thrown up in the vertical plane. Let t1, t2 and t3 are the time taken to cross the window W1, W2 and W3 respectively and ΔV1, ΔV2 and ΔV3 are the magnitude of change in speed after respective window cross. Mark the CORRECT option(s).

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Average speed of the particle passing the windows may be equal if W1 < W2 < W3

Average speed of the particle passing the windows may be equal if W1 > W2 > W3

If W1 = W2 = W3, the change in speed of the particle while crossing the windows will satisfy ΔV1 < ΔV2 < ΔV3.

If W1 = W2 = W3, the time taken by particle to cross the windows will satisfy t1 < t2 < t3 .

answer is C.

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Detailed Solution

As going up, speed of the particle is decreasing and hence the time taken in crossing the windows will be t1

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