Questions
A 25 wad and a 100 watt bulbs are joined in series and connected to the mains. Which bulb will glow brighter ?
detailed solution
Correct option is A
Resistance of 25 watt bulbR1=V2P=(220)225=1936ΩResistance of 1oo watt bulbR2=V2P=(220)2100=484ΩSeries resistance =R1+R2=2420ΩCurrent through combinationi=2002420=111Voltage across 25 watt bulb=R1×i=193611=176 volt Voltage across 100 watt bulb=R2×i=(484/11)=44 volt Hence 25 watt bulb will glow brighterTalk to our academic expert!
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A resistor R is connected across a battery of emf 12 V. It observed that terminal potential differenceis 9 V and the power delivered to resistor is 18 W. Internal resistance of the battery ‘r’ and the resistance R are respectively
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