A wagon of $$200$$ kg is moving on a smooth track with velocity of $$2$$ $$m/$$$$sec$$. A man of $$80$$ kg also runs in the wagon with a velocity such that speed of the centre of mass of the system is zero. Find the velocity of man relative to the wagon (in$$ $$m/s).

Question

Infinity Learn · Accepted Answer

Velocity of centre of $$massvcom=$$ mwagon×$$vwagon+massman$$×$$vman(mwagon+mman)vcom$$ $$=$$ $$(200)(2)+(80)(V)280$$ $$=$$ $$0$$ ⇒ V $$=$$ $$-5$$ $$m/svman$$→ $$=$$ v→ man, wagon $$+vwagon$$→vman, wagon→ $$=$$ vman→$$-vwagon$$→ $$=$$ $$-5-2$$ $$=$$ $$-7$$ $$m/s$$      $$-ve$$ sign indicates opposite direction.

A wagon of 200 kg is moving on a smooth track with velocity of 2 m/sec. A man of 80 kg also runs in the wagon with a velocity such that speed of the centre of mass of the system is zero. Find the velocity of man relative to the wagon (in m/s).

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