A wall has two layers A and B each made of different materials. Both the layers have the same thickness. The thermal conductivity of material A is twice of B. Under thermal equilibrium the temperature difference across B is 360. Then the temperature difference across A is
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a
6°C
b
16°C
c
18°C
d
24°C
answer is C.
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Detailed Solution
Thermal resistanceR=ℓKA∝1KKA=2KB∴RA=RB2So, let RA = R then RB = 2RNow, HA = HB∴(T⋅D)ARA=(T.D)BRD or (T.D)A=RARB(T.D)B=R2R36∘C=18∘C
A wall has two layers A and B each made of different materials. Both the layers have the same thickness. The thermal conductivity of material A is twice of B. Under thermal equilibrium the temperature difference across B is 360. Then the temperature difference across A is