First slide
Viscosity
Question

Water is allowed to flow through a capillary tube of length 10cm and diameter 2 mm under a constant pressure difference of 6.5 cm of water level. If 0.16 litres of water flows in 1 minute, its coefficient of viscosity is,

Easy
Solution

\large l=10cm;\;r=10^{-1}cm
\large h=6.5cm,\;V=0.16lt=0.16\times10^3\;cm^3
\large t=1min.=60sec.
\large \frac Vt=\frac {\pi Pr^4}{8\eta l}\Rightarrow \eta =\frac {\pi r^4\rho ght}{8Vl}
\large =\frac {3.14(10^{-1})^4(1)(6.5)(980)(60)}{8(0.16\times10^3)}(10)=0.00937\;poise

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