First slide

Surface tension

Question

A water drop is divided into eight equal droplets. The pressure difference between the inner and outer side of the big drop will be:

Moderate

A

same as for smaller droplet
B

(1/2) of that for smaller droplet
C

(1/4) of that for smaller droplet
D

twice that for smaller droplet

Solution

$R = n^{\frac{1}{3}} . r = 8^{\frac{1}{3}} r \Rightarrow R = 2 r P_{ex} \infty \frac{1}{R} \Rightarrow \frac{{(P_{ex})}_{big}}{(P_{ex)_{small}}} = \frac{r}{R} = \frac{1}{2}$
$p_{d i f f} = p_{s m a l l} - p_{b i g}$ = $p_{b i g} = \frac{p_{s m a l l}}{2}$

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