Water is flowing in a river at 2 m s-1. The river is50 m wide and has an average depth of 5 m. The power available from the current in the river is (Density of water = 1000 kg m-3)

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0.5 MW

1 MW

1.5 MW

2 MW

answer is B.

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Detailed Solution

Power = Kinetic energy of water flowing per second= 12×area of cross-section × density ×(velocity)3= 12×50×5×1000×23W = 106W =1MW

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