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Q.

Water is flowing through a horizontal pipe of variable cross- section. The rate of volume flow is 0.8 lit/sec . The pressure is 40,000pa at a point where the area of cross-section is 4×10−4m2. The pressure at the point where the area of cross-section 10−4m2 is

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a

6000Pa

b

10,000Pa

c

36000Pa

d

24000Pa

answer is B.

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Detailed Solution

V=0.8×10-3m3=A1v1=A2v2 v1=VA1=0.8×10-34×10-4=2m/s & v2=VA2=0.8×10-310-4=8m/s  p1+12ρv12=p2+12ρv22 40000+12ρVA12=p2+12ρVA22 p2=40000+12ρv12-v22=40000+12×100022-82=10000Pa
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