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Q.

Water flowing through a horizontal pipe of variable cross section. The rate of volume flow is 0.4lit/ sec. The pressure is 60,000 pa at a point where the area of cross section is 5×10−5m2 . The pressure at a point where the area of across section 10−4  is

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a

48,000pa

b

72,000pa

c

60,000 pa

d

84,000 pa

answer is D.

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Detailed Solution

A1v1=A2v2                 0.4×10−3=5×10−5×v1                 v1=4×10−45×10−5=405=8m/sec                 A2v2=0.4×10−3                 10−4v2=0.4×10−3⇒v2=4m/sec                 p2−p1=ρ2(v12−v22)=10002(64−16)=10002(48) = 24,000                p2−60,000=24,000⇒p2=84,000pa
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