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Q.

Water flows in a streamlined manner through a capillary tube of radius a, the pressure difference being P and the rate of flow Q. If the radius is reduced to a/2 and the pressure increased to 2P, the rate of flow becomes

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a

4Q

b

Q

c

Q4

d

Q8

answer is D.

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Detailed Solution

V=πpr48ηl ∴V∝Pr4 (η and l are constants )∴V2V1=P2P1r2r14=2×124=18∴V2=Q8
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