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Q.

Water flows through a capillary tube of radius R and length L at a rate of 100 m3s−1 when pressure difference is 100 mmHg. If another tube of same length but twice radius is connected in parallel, then the total rate of flow of water through the two tube (for twice the pressure difference) will be:

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a

1700 m3s−1

b

1700/16 m3s−1

c

1600 m3s−1

d

3400 m3s−1

answer is D.

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Detailed Solution

Q=πPr48ηlFor parallel, pressure difference P is same and Qnet =Q1+Q2here Q2 is 16 Q1 (P increases by 2 times and r increases by 2 times)
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